The ratio test is looking like a great
test.
Does it always work?
[SOUND].
Let's recall what the ratio test says.
I'm going to be considering a series the
sum of
a sub n and goes from zero to infinity.
And I'm going to assume that all of the
terms that
I'm adding up, all of the a sub ns, are
non-negative.
So a sub n is greater than or equal to 0.
And the ratio test tells me to consider
the limit of the ratio of
subsequent terms, so I'm taking the limit,
as n approaches infinity of a sub n
plus 1 over a sub n, and I'm calling that
limit L.
And then what does the ratio test tell me?
Well the ratio test tells me that if that
limit is less than 1, then the series
converges.
If that limit is bigger than 1, then the
series diverges.
But if the limit is equal to 1 then the
ratio test is inconclusive.
So what happens when l equals one?
Well supposedly the ratio test doesn't say
anything in that case.
But if we listen really carefully, is
there something that we
can get out of the ratio test even when l
equals one?
No.
Whoa, okay, but why not?
Well there are cases where l equals 1 and
the series converges.
But then there are also cases where
L equals one and the series diverges.
Can we actually see some of these
examples?
Here's an example but maybe a silly
example where L
is equal to 1 but the series will end up
diverging.
So let's try this.
Here's the example, it's the sum, n goes
from 0 to infinity of the number 1.
[LAUGH]
well, I mean this, this definitely
divergences, right?
If you keep adding up 1 plus 1 plus 1,
right, that's not a finite number.
So this is a divergent series.
But of course, in this case, what's a sub
n?
Well a sub n doesn't depend on n, it's
just always 1.
And so the limit of the n + 1th term over
the nth term as n goes to infinity
is just 1, because a sub n plus 1 and a
sub n are both 1.
What about an example where the series
converges even though L equals 1?
So on an example where the L in the ratio
test is 1, but the series ends
up converging even though the ratio test
doesn't tell us that.
So let's see an example.
An example of this is the sum and
goes from 1 to infinity of 1 over n
squared.
THis series we've already seen to
converge.
It converges by, let's say, the p series
test.
It's a p series where p equals 2.
But, what is l in this case.
Well, the nth term in the series a sub n,
is 1 over n squared.
So l is the limit of a sub n plus1 over a
sub n, as n
goes to infinity.
And in that case, that's
the limit as n goes to infinity of 1 over
n plus 1 squared.
Divided by 1 over n squared and that limit
is indeed 1.
But how do
I know that the limit is 1?
Well, to compute this limit, I
could first rewrite this as the limit as n
approaches infinity
1 over what, I must gotta move the n plus
1 squared in the
denominator so it will be n plus 1 squared
over n squared now
[INAUDIBLE]
expand it out to the n plus 1 squared this
be the limit and as n
approaches infinity 1 over n squared plus
2n plus 1 that's what I
got expanded n plus 1 squared, divided by
n squared, And this is the sum here
in the numerator and I got split this up
into three separate fractions.
This is
the limit as n goes to infinity 1 over n
squared over n squared, plus two n over n
squared
plus one over n squared.
Now I could simplify this a bit more too.
This is the limit n goes to infinity of
one over n squared over n squared is one.
2 n over n squared is
2 over and and 1 over n squared I'll just
write as one over n squared.
Well what's the limit?
When and is very large, this is very close
to 0 and this is very close to 0.
So when n is very large, this is 1 over 1
plus a number close to 0 plus a number
close to 0.
This limit Is 1, which is exactly what I'm
claiming.
So when we say that the ratio
test is silent when l equals 1, it's not
for a lack of understanding.
There really are series that converge and
series that diverge.
In both cases, l equals 1.
[NOISE]