1 00:00:00,210 --> 00:00:04,245 Why am I dong any of this? 2 00:00:04,245 --> 00:00:05,020 [SOUND] 3 00:00:05,020 --> 00:00:11,257 Sequences are useful for a variety of reasons. 4 00:00:11,257 --> 00:00:16,017 For starters, sequences help us understand repetitive processes, and some of 5 00:00:16,017 --> 00:00:20,791 those repetitive processes are useful if we're trying to compute something. 6 00:00:20,791 --> 00:00:22,640 Well here's an example of such a process. 7 00:00:23,990 --> 00:00:30,282 I'll define a sequence recursively, X sub n plus 1, we want 8 00:00:30,282 --> 00:00:33,450 over X of n, plus X of n over 2. 9 00:00:33,450 --> 00:00:38,480 Maybe I'll start with the first term of this sequence, as just being 1. 10 00:00:38,480 --> 00:00:42,240 Lets start with X of 1 equals 1, and see what we get. 11 00:00:42,240 --> 00:00:48,512 Well X of 2 is 1 over X of 1, which is 1, plus 1 over 2, 12 00:00:48,512 --> 00:00:56,310 that's 3 halves. We could also try to calculate X of 3. 13 00:00:56,310 --> 00:00:58,980 I get that by taking 1 over X of 2. 14 00:00:58,980 --> 00:01:04,590 So 1 over 3 halves, and adding that to 3 halves over 2. 15 00:01:04,590 --> 00:01:10,828 Now to do that calculation, or I can write 1 over this fraction as 2 3rds. 16 00:01:10,828 --> 00:01:16,813 And instead of writing 3 over 2 divided by 2, I'll write that as 3 4ths. 17 00:01:16,813 --> 00:01:16,890 . 18 00:01:16,890 --> 00:01:20,210 I'll put this over a common denominator of 12. 19 00:01:20,210 --> 00:01:21,434 So 2 3rds 20 00:01:21,434 --> 00:01:27,690 is 8 12ths, and 3 4ths is 9 12ths. 21 00:01:27,690 --> 00:01:32,630 So all together X sub 3 is 17 12ths. 22 00:01:32,630 --> 00:01:35,790 We can compute more terms with the help of a computer. 23 00:01:35,790 --> 00:01:38,190 Here's the X sub 2 term that we just calculated. 24 00:01:38,190 --> 00:01:42,458 You can compute the next term, the X and 3 term is 17 12ths. 25 00:01:42,458 --> 00:01:45,374 The X and 4 terms is 577, 408ths. 26 00:01:45,374 --> 00:01:46,844 Here's the X and 27 00:01:46,844 --> 00:01:51,464 5 term, in which you'll notice is that these terms 28 00:01:51,464 --> 00:01:56,920 are getting closer and closer to the square root of 2. 29 00:01:56,920 --> 00:02:02,410 Even X of 3, which is 17 12ths, is close to the square root of 2. 30 00:02:02,410 --> 00:02:03,800 Lets see how that works. 31 00:02:03,800 --> 00:02:06,768 So I want to try to convince you that 32 00:02:06,768 --> 00:02:11,750 17 12ths, is approximately the square root of 2. 33 00:02:11,750 --> 00:02:14,335 Well if I square both sides what do I get? 34 00:02:14,335 --> 00:02:18,580 I'm getting that 17 squared divided by 12 squared. 35 00:02:18,580 --> 00:02:22,860 Should be approximately 2. And what's 17 squared? 36 00:02:22,860 --> 00:02:25,210 Well 17 squared is 289 and 12 squared is 144. 37 00:02:25,210 --> 00:02:29,800 And is 289 over 144 close to 2? 38 00:02:29,800 --> 00:02:39,660 Yeah, because the numerator is just about twice the denominator. 39 00:02:39,660 --> 00:02:43,970 So one way to think about the square root of 2, is by thinking about the sequence. 40 00:02:43,970 --> 00:02:49,085 If you want to find a really good approximation of the square root of 41 00:02:49,085 --> 00:02:54,098 2, all you've gotta do is go far enough out in this sequence. 42 00:02:54,098 --> 00:02:58,982 [SOUND] 43 00:02:58,982 --> 00:03:02,410 [SOUND]