Hi everybody. Up to this point in the course Charles and I have presented already a lot of material. Which included both material that can be found in traditional quantum mechanical text books and also some non standard exposure to quantum physics for example super conductivity path integrals some elements of quantum localisation, etc, etc. And I have to say, on my side, the preference has been for the latter. I want to tell you more, about things that we cannot find in traditional textbooks. But today is certainly going to, going to be an exception, because today I'm going to present a very traditional quantum mechanical problem that no reasonable quantum mechanical course can avoid, and this is the problem of a harmonic oscilllator. So the reason I cannot avoid this problem is two-fold. So first of all quantum harmonic oscillator, the problem of quantum harmonic oscillator is relevant to a variety of various experimental systems, ranging from cold atoms who are atoms that are trapped in a quadratic potential, to let's say molecules who's low energy oscillations are described by harmonic oscillator, to quantization of light, to quantization of oscillations increase those so-called [UNKNOWN]. We're going to actually discuss them soon. And many, many other things. And second, so the problem, on the theoretical side, the solution to the problem of harmonic oscillator, is very illuminating and useful, in that it gives you very useful tools, so-called creation and anti-elation operators that are useful in a variety of context across various fields of physics. And you're going to see this thing very often in other courses if you pursue. physics states. But before solving the quantum harmonic oscillator problem, let me remind you the story behind the classical harmonic oscillator. And here I have an example of the classical system which exhibits these small oscillations and near an equilibrium position. And these oscillations exactly are the harmonic oscillator motion. So, on the, mathematical side, what happens here, of course, is that, the, mass here experiences, the so-called Hook's force, which is proportional to the displacement x of the, spring relative to its equilibrium position. So let's say here if this is my x axis, and let's say we have an equilibrium position somewhere here so this is my zero. So this is x, and the force is proportional to the displacement, and in this case at this moment of time it's this Hook's force. X in this direction, in the negative x direction. Now, I can write this force, of course, as a minus gradient in this case it's just one-dimensional gradient, or just the derivative with respect to x, of some potential. And to produce a linear force, of course, I need to differentiate a quadratic potential. So in this case is kx square over 2 and this is exactly the potential energy of the harmonic oscillator that eventually is going to appear in our Schrodinger Equation in the quantum version of this problem. Now the classical side though, what I have to do is I have to solve the second Newton law presented here. So, and the second Newton law, of course, is just mass times acceleration, the second derivative of x is equal to all the forces. In this case, there is just one force, in this example, it's if we ignore gravity, which is not going to modify too much. but in this case, it's going to be just one force which is the force due to the Hook's law. And if I write this equation, if I divide this equation by m and instead of writing the second derivative, I will write it in the compound form x with two dots on top So I can write it as x two dots, plus omega squared x, is equal to 0. Where omega, is equal to the square root of k over m. And the solution to this, differential equation is the sines, or cosines to some arbitrary phases, and it's up to us, which, solution to choose. So there will be, some amplitude here, amplitude here, so we can choose a sine or we can choose a cosine. And as long as we have two free parameters which will determine the initial conditions, the initial position and the initial velocity, these are all general solutions. And solve these classical problems so let me choose for example the sin solution and present it here. So this is this solution to this harmonic oscillator. Now to move further let me choose a particular intial condition which I can do which corresponds to x of t equals zero being zero. So let's say the initial moment of time the position of our harmonic oscillator was exactly at the equilibrium point just for simplicity and in this case this is my solution. Now if I want to find the velocity of the oscillator as a function of time, so all I have to do is differentiate the position, and in this case it's going to be just x naught. Some amplitude of oscillations times omega times cosign of omega t. So what I can do now, I can ride the energy of the system which is not a function of time as we shall see in accordance with the conversation law. Which would be a sum of the kinetic energy and m v squared over 2, and the potential energy v of x, which is equal to one half k x squared. k is the coefficient in the Hooke's law, or expressing it through the mass and the, and frequency, I can write it as so, one half, m omega squared, x squared. And, this is by the way, the form in which typically appears in the literature, in particular in quantum mechanical literature. So, now, indeed if we plug in this result into the energy. So, the energy is going to be equal to mv squared over 2. So, we're going to have m over 2 x naught squared, omega squared, plus cosine squared of omega t. From this velocity term and potential energy plus m by two x squared, x not squared, omega squared from here, sine squared of omega t, and then we use the fact that cosine squared of an arbitrary angle plus and sine squared of the same angle is equal to one. And so we see that indeed the energy is simply this. So and the energy is conserved. Indeed in a, cor, in, in accordance with the energy conservation law. But of course, even though the energy E here, is not a function of time, the two terms in this equation, the kinetic and the potential energy are functions of time. So x is a function of time and the velocity is a function of time. but they work in unison with one another in such a way that their sum, the sum, is a constant. And if we plug this, so let's say the x. X axis here is going to be m omega times the coordinate, and the y coordinate here is going to be the momentum. So we see that this trajectory basically in the face space describes the motion of a harmonic oscillator. It's a motion on a circle. and the radius of the circle is determined by the energy of our harmonic oscillator that we. And this motion is a phase portrait of this classical system. And, by the way, I will just mention in passing that there is a relation between the phase portrait of the classical system and the corresponding spectrum of quantum systems. But that's the only thing I'm going to say here in this regard. So now let us move closer to the main subject of today's lecture and make the oscillator quantum. So the motivations to do so are many, as I said. So, for example, we can think about instead of having a classical mass and a spring, we can talk about, let's say a two-atom molecule and the oscillations of this molecule relative to the equilibrium position of the atoms. So at low energies these oscillations are going to be described by a quantum harmonnic oscillator. So of course there are many more examples as I mentioned in the beginnning of the lecture. Let me just mention another one, so for instance Talking about the behavior of a quantum particle in a rather arbitrary potential v of x so lets say somethign like this. So if we are interested in low energy behavior the particle somewhere near the minimum of the potential, we can always Expand the potential view effects near the minimum, so it's going to be v of x naught, so this point plus v prime of x naught x minus x naught. And this is zero because this is the minimum, plus the second derivative over 2x minus x not squared. And model of this overall constant, which is, just shifts the minimum of energy and this shift of the equilibrium position. And this shift of the equilibrium position. So the remaining part of this potential is really the quadratic potential that we have in the harmonic oscillator problem. So what I'm saying here is that you can always almost always approximate a reasonable potential, well near the minimum of the well with the harmonic oscillator if you have a small function. Of course if you have square quantum well we can not do that but in most cases you have a smooth potential and in this case we can just replace it at low energies with this harmonic oscillator. Okay, now let me raise this stuff and move further so how to formally go from the classical harmonic oscillator in this but does show the quantum harmonic oscillator. So, to do so we have to pretty much do the following mathematical procedure. We can just put a hat here. And that's it. So that's how me made the oscillator quantum. So well seriously what we have to do, we have to replace the energy of the oscillator. So the energy we derived in the previous side for the classical harmonic oscillator. So now we replace the energy of the oscillator with the Hamiltonian which is an operator the momentum which is just a variable in the classical description, now we replace it with the operator that acts on the wave function. And in principle we can put a hat also on top of the cord metal, though with the action of the cord metal on a wave function in position space, is pretty simple action. It's just a multiplication operator, but this pretty much what what it means on the mathematical side to make, to go from classical description with no operators involved to a quantum description with operator involved. So this is the mapping, and the problem that we want to solve now is to find solutions to the Eigenvalue problem. So of course its a non its a time independent problem so there is no time involved and what we want, we want to find a solution to this equation. So when solving this Schrodinger equation and in particular when thinking about the allowed energy levels. So what we should keep in mind about this harmonic oscillator potential is one property which makes it very different from what we have seen before. Namely that this potential grows. The potential energy grows indefinitely to infinity as x become very large or very negative. So there is no room here for plane wave-like solutions propagating to infinity, and the only thing we may have here, are discreet states, corresponding to particles localized in the vicinity of this x equals 0. And to determine this these energy levels, these harmonic oscillator spectrum Is exactly the main problem we're going to be focusing on in the next couple of videos.