Superconductivity is an example of an intrinsically many bodied quantum method, which doesn't really have a single particle counterpart. So it cannot be really understood based on just a single particle Schrodinger equation. So in the context of superconductors, of course, these many particles are electrons. So that play together in some sense to create this amazing quantum coherent state. Now, to understand the very complicated array of many, Body quantum phenomena. The first step is to understand the concepts of quantum statistics. Which is an increasing quantum interaction between identical particles. It doesn't really have a classical counterpart. So unlike let's say the electrostatic let's say [UNKNOWN] which depends on distance between the two charges. So this statistical interaction between identical particles is quite different. It appears to never have identical particles and they feel each others presence. independently of the distance separating them, so this is very interesting. And so we're going to learn about it and also we are going to learn about the two fundamental classes of particles, with respect to their quantum statistics, that are called bosons and fermions. And those guys they lose energy space, [INAUDIBLE] was very much drastically different. And we will see that it's actually a transition in some sense from fermion like behavior, to boson like behavior. That is exactly what explains transition from a regular metal into a quantum superconductor. The first step in defining quantum statistics. Let us consider two identical quantum particles. This blue represented by these blue dots here. And let's assume that all intrinsic properties of these particles are exactly the same. And so the question I'm going to be asking is what happens if we braid two particles? So, in other words, if these two particles exchange places. So the first particle goes to the place of the second one and vice-versa. So what it means is that the wave functions. In this case, the wave function describing this two, this two particle system depends well, on the coordinates of, of these two particles, r1 and r2, in principle, some other quantum numbers that I'm not writing. And so the question we're asking is what happens with this wave function if we replace r1 with r2, and otherwise errors. So it turns out that upon this braiding the wave function requires quantum mechanical phase. So this is statistical phase phi. And well we can sort of get an idea of why it might happen. Because the wave function really is a tool for us to understand the observable phenomenon, most observable answer. Through the let's say the absolute value of the wave function or the various metric elements wave function phase is not something we worry about. And so we may imagine that even though from our perspective nothing has changed since two particles are identical which one is at which point doesn't really matter. So we still main principle get a quantum mechanical phase here, and indeed this happens, okay? So and so the question that we can ask, and that was asked a long time ago what are the possible values of this quantum statistical phase? And the answer was provided in this seminal paper entitled The Connection Between Spin and Statistics, by Wolfgang Pauly, who proved there exists a one-to-one correspondence between the internal angular momentum of a particle, so called Spin that you're going to learn about a little later in the course and it's quantum statistics so I want to give you a lecture on spin because there will be a separate one on that but that will just mention that their are just two types of particles allowed in nature which have either integer or half integer spin. And those differ by how their wave functions transform under rotation. So if we rotate our [INAUDIBLE] coordinate system by a certain angle of this rotation [INAUDIBLE] that we would encounter would look differently depending on what kind of spin of the particle has. And, interestingly enough let's say spin one half particles an electron is an example of such a particle. is going to be described by simple representation of this rotation. Which upon repeating it by 360 degrees, actually picks up a minus sign. As opposed to integer spin particles, or particles with no spins that don't really change. Whose wave function doesn't really change upon this rotation by 360 degrees. Now I'm just sort of giving you a flavor, but the outcome of this so-called spin statistics theory can be formulated in a very simple way. So if a particle with integer a internal angle and momentum including zero the phase here is really zero, so there is no change in the wave function. If we replace r one bl-, by r2, nothing changes. Well, for particles with a half integer spin this statistical [INAUDIBLE], phi is equal to pi. Or, in other words, this psi of r1 and r2 is equal to minus of psi of r2 and r1. And these guys with half integer spins are half integer spin are called fermions. So, we'll just make one comment that it turns out that this classification is specific to a three dimensional relativistic quantum theory to the world that which we actually leave but if we consider two dimensional systems which appear as a matter of fact in, let's say in condensed measure context. So we have two dimensional metals and two dimensional super conductors. So there it turns out that the possibilities for phi are much more interesting. So apart from zero and pi we may have an extra arbitrary phase of pi, which are called in the particles like that, so the fictitious immersion particles like that are called anions this pi can be a matrix in which case they are called [UNKNOWN] in news but this is the only thing I'm going to mention about it. But it just, I want to want you to know that the parts of these well known possibilities for fundamental particles. So there are other situations which arise in a [UNKNOWN] manner of physics. But now let me focus on this case. So well, so we for irregular particles we have I, either a zero or pi. So let's assume we're dealing with fermions, let's say we're dealing with electrons. So what are the consequences of this minus sign that we pick up in front of the wave function. Does it really matter at all, so should we worry about it? So let us think about it. So what we're really saying again is that psi of r 1 and r 2 is equal to minus of psi of r 2 and r 1. And it immediately leads to a conclusion that for an important case r 1 equals r 2. So psi of r 1 and r 1 is equal to minus of psi of r 1 and r 1. Which means that the size is equal to 0. So what does it mean? It means that the probability of find two identical fermions in the same point is 0, because the size is 0. So, well and It means that no two particles can be like no two fermions. Identical fermions cannot occupy the same point. And more generally we can actually generalize this for an arbitrary representation of the way function. We can prove and what this is about exclusion principle is that no two identical fermions cannot occupy the same quantum state. They cannot have exactly the same quantum numbers. But there is no such constraint for bosons okay. So, this has very important consequences so this statement again is called the Pauli exclusion principle and for bosons it doesn't apply. So, and that the consequences are that if we have certain quantum state, let's see an [UNKNOWN] quantum state i and we want to populate this state with fermions, there are only two possibilities for the occupation number of this state. So the occupation number can be either 0 or 1. Well for bosons, it can be anything, it can be any 0, 1, 2, can put any, any number of bosons we want in this quantum [INAUDIBLE] . Now what does it mean in the context of many body systems, when we have actually more than one and two particles, when we have billions and billions of identical particles as we usually do in quantum systems such as, let's say, metals and superconductors? So let us discuss this question first on for many bosons system. And what we're actually asking is what happens let's say if we have many energy levels that are initially empty and we want to know what happens if we sort of pour identical bosons into this Prescribe, landscape of quantum states, with some states I with some energy E, energy E sub I. And more specifically what we're asking is, what we're interested in is what is the lowest energy state, the so called ground state, that the system would want to, Form at low temperatures. So at low temperatures the excitations are going to sort of calm down and the system would want to form the lowest energy state. Now since any number of bosons can occupy any state, so clearly the lowest energy state would correspond to essentially a state in which all bosons, non-interacting bosons that is, are sitting just at the lowest possible level. Now for a free particle with dispersion, just having the kinetic energy dispersion p squared over 2 m. Some sort of parabolic dispersion here, I'm just plotting it in sort of an example of a two-dimensional system px, py and this is the energy basically all bosons would want to drop into the zero momentum state. Okay, and this kind of state is called Bose-Einstein condensate. The state in which a single quantum mechanical level in this case the state was zero momentum, zero velocity is microscopically occupied. So this kind of phenomenon has been known for a long time, since Einstein. But it was sort of, very observed in the clear way, only very recently in 1995 first. Now it's observed routinely in various laboratories including our own joint quantum institute. But back in 1995, it was new. And, this discovery was actually awarded 2001 Nobel Prize in physics. So here, I'm showing the [INAUDIBLE] . So, basically, what the experimentalists did. They trapped atoms, bosonic atoms in a confined geometry in this certain trapping potential. And cooled them down to ultra cool temperatures. And then let them remove the trap. And let them expand. And they just sort of took photographs of these atoms as time went by. And they saw this pic. So this is basically the so called time of flight extension. And this pic is shows the population. The density of particles in real space. Large number of particles sort of don't, move too much, as time goes by. And this speaks sort of [COUGH] in real space is [UNKNOWN] of condensation and [UNKNOWN] space. So this corresponds to particles with zero velocity so the just sort of stay still. So now I would like to mention a very important circumstance namely that. This Bose-Einstein condensates may host a very interesting phenomenon of superfluidity where a condensate of interacting bosons form a superfluid which has exact 0 viscocity and which can flow therefore without resistance. So, here for example I'm showing a photo of superfluid. Helium in a cup, the helium which can actually escape the cup climbing up the walls. So let me mention that superfluidity, the phenomenon of superfluidity has actually been known for a very very long time. Since 1937 it was discovered then in Helium by Pyotr Kapitsa. And, and Kapitsa got his Nobel prize for this discovery of 1978. Well, it would be too late, 40 years after the initial discovery. So the mathematical theory of superfluidty was put together by Lev Landau a famous Russian theorist who got his Nobel prize for this theory in 1962. So actually before Kapitsa and hey, let me just mention that the You know this noble prize was awarded to him after Lev Landau got into a very serious accident. Everybody thought he wouldn't survive but by some miracle he lived for a few more years. And this allowed the Nobel community to award him long overdue Nobel prize. So, in any case, I'm not going to mention. I'm not going to talk too much about the theory of superfluidity now because it actually requires understanding of the interactions in Bose-Einstein condensates, and this is a non-trivial business interacting many-body states. But I will just that, superfluidity sort of rings a bell in the context of superconductivity because. If we want to explain the main property of a superconductor, namely the zero resistance state of the superconductor, we would want essentially a superfluid of electrons, which would move with zero viscosity and without resistance. This is exactly what the doctor had as prescribed, but there is one little problem with this explanation of super, superconductivity, namely well electrons in the metal are not [INAUDIBLE], they have half of half of the [INAUDIBLE], so they spin one half, so they're [INAUDIBLE], so they do not form a superfluid. So, what do they do? And, to answer, to answer this question, I need to consider the ground state of many-fermion system now. We talked about the ground state of bosons. Now let me talk about what happens with fermions if I pour them into a given energy landscape. Let's say I have, Has some available levels and they have a many fermion system that would want to occupy those levels and the question is, How will I minimize energy? So due to the power of exclusion principle I cannot allow my fermions to be sitting on the same lowest energy state. So I can only at minimized energy, can only sort of stack them up one by one to the lowest energy states as so until they reach the the certain level called the fermion level or fermion energy up here and basically this is the picture of fermion ground state, which is quite different from bosonic ground state. Now in the context of a metal and three dimensional, three dimensional metal, so what we have Is well our energy landscape is given by the usual disbursement relation. The energy versus momentum is equal to p squared over 2m. So what I need to do in order to sort of satisfy the same picture with this energy is that I will occupy all momentum stays. So here I have k x, k y,k z ,or I could have written p x, p y, and p z. So below certain momentum is called fermion momentum I will have all states occupied just like I have here all these levels occupied and while these levels are all empty. So and the threshold momentum it is just ignore this red and white dots for the moment. So below this threshold momentum. I have all states occupied above this threshold momentum I have all states empty and this is exactly the picture which describes electrons in, in metals. Actually it works amazingly well for metals. And it's also known that the typical Fermi temperature in metal, the Fermi temperature being the threshold momentum here The p, pF square divided by 2m this is the Fermi energy divided by the Bols, Bolsman constants or constant which converts energy into the temperature. So if we do this calculation the typical Fermi temperature in the metal would be around 10000k, which is huge so even if the room temperature left alone at 4 kelvin so this energy scale is normal as compared to all other energy. [UNKNOWN] So and what the temperature, well Fermi temperature usually does is it excited electrons from below the thermo surface. For instance I can not excite electron from here to here. I can not move, so let me just draw this paralysis and then I will say it's not allowed. So have, let's say, an electron here, I can move it to this point, it's not a lot. Because both the stays are occupied. So this stay is already occupied. So power exclusion wouldn't allow me to do this thing. So, but what I can do if I have temperature, I can, I have some energy to spend, so I can excite an electron let's say from here to here. And so the y point here is an empty space that the electron leaves behind. It's called a hole and the red one is the actual electronic excitation. And this is exactly the picture of a metal and so this guys, basically this red guys and this white guys. these guys form basically they are the linked leaders in a typical metal. But they do not condense, they don't form a super fluid. They just move around and experience scattering you know from one point to a different point and this result in a finite resist. So how do you reconcile this picture of a metal with the presence of super conductor is that is observed at low temperatures. So this was again a major mystery for many many years, was not at all obvious how to do this. But of course there is a hint about it due to the presence of superfood so sort of in retrospect it's pretty natural to ask whether or not it's possible to somehow convert to electronic liquid [UNKNOWN] liquid Into a bosonic superfluid. So this guys are fermions, so they're not bosons. So can we make a bosonic superfluid out of a fermionic gas such as here? Well, it's difficult unless, so unless I allow my electrons to form composite objects. Of two electrons states whose total spin is either one or a zero. Remember the speed of a single electron is one half but if I combine the two of them together, so it's going to be an integer. So they are going to be boson. And so if I somehow find a way to say force objects well I could have actually drawn it like this but well knowing the results, I'm drawing these objects this week. But this station doesn't matter. So if I allow the formation of to electron states, this, these 2 electrons states are going to be bosons. And these bosons would be able to condense. And these guys would be able to form a super-fluid now, a charge super-fluid. And this is great because this state will superconduct. And this is exactly what happens and this is bound states of two electrons called Cooper burst. And from this perspective superconductor is a Bose-Einstein condensate of cooper burst. But the main question remains is why would this Cooper burst would form? Why would such states appear? And this is the question that we're actually going to answer in the remaining two segments. And we're going to solve the cooper pairing problem. And this was also established connection between this lecture and the previous lecture. When we discussed, [INAUDIBLE] states and weak potentials.