Results from the Receiver
      Error module reveals several properties about digital
      communication systems.
      
- 
	  As the received signal becomes increasingly noisy, whether
	  due to increased distance from the transmitter (smaller
	  αα) or to increased noise
	  in the channel (larger
	  
	    
	      
		N
		0
	      
	    
	  
	      
		N
		0
	      
	    ), the probability the receiver makes an error
	  approaches 1/212. In such
	  situations, the receiver performs only slightly better than
	  the "receiver" that ignores what was transmitted and merely
	  guesses what bit was transmitted. Consequently, it becomes
	  almost impossible to communicate information when digital
	  channels become noisy.
	 
 -  As the signal-to-noise ratio increases, performance
	  gains--smaller probability of error  
	  
	    
	      
		p
		e
	      
	    
	  
	      
		p
		e
	      
	     -- can be easily obtained. At a signal-to-noise
	  ratio of 12 dB, the probability the receiver makes an error
	  equals
	  
	    10-8
	  
	      
	      10
	      -8
	    .  In words, one out of one hundred million bits
	  will, on the average, be in error.
	 
 -  Once the signal-to-noise ratio exceeds about 5 dB, the
	  error probability decreases dramatically. Adding 1 dB
	  improvement in signal-to-noise ratio can result in a factor
	  of 10 smaller
	  
	    
	      
		p
		e
	      
	    
	  
	      
		p
		e
	      
	    .  
	 
 -  Signal set choice can make a significant difference in
	  performance. All BPSK signal sets, baseband or modulated,
	  yield the same performance for the same bit energy.  The
	  BPSK signal set does perform much better than the FSK signal
	  set once the signal-to-noise ratio exceeds about 5 dB.
	
 
    
    
    
    
	
	  Derive the expression for the probability of error that
	  would result if the FSK signal set were used.
	
       
	  The noise-free integrator output difference now equals  
	  
	    αA2T=α
		    
		      E
		      b
		    
		  2
	  
	      
	      
		
		α
		
		  
		  A
		  2
		
		T
	      
	      
		
		
		  
		  α
		  
		    
		      E
		      b
		    
		  
		
		2
	      
	    . The noise power remains the same as in the BPSK
	  case, which from the probability of error equation yields
	  
	  
	     p e=Qα2EbN0
	  
	      
	       p e
	      Q
		
		  
		    
		      
			α
			2
		      
		      Eb
		    
		    N0
		  
		
	      
	    .
	
 
    
      The matched-filter receiver provides impressive performance once
      adequate signal-to-noise ratios occur. You might wonder whether
      another receiver might be better.  The answer is that the
      matched-filter receiver is optimal: No other receiver
      can provide a smaller probability of error than the matched
      filter regardless of the SNR. Furthermore, no signal
      set can provide better performance than the BPSK signal set,
      where the signal representing a bit is the negative of the
      signal representing the other bit. The reason for this result
      rests in the dependence of probability of error
      
	
	  
	    p
	    e
	  
	
      
	  
	    p
	    e
	  
	
      on the difference between the noise-free integrator outputs: For a given 
      
      
	
	  
	    E
	    b
	  
	
      
	  
	    E
	    b
	  
	, no other signal set provides a greater difference.
      
     How small should the error probability be? Out
      of NN transmitted bits, on the
      average
      
	N
	    
	      p
	      e
	    
	  
      
	  
	  N
	  
	    
	      p
	      e
	    
	  
	 bits will be received in error. Do note the phrase "on
      the average" here: Errors occur randomly because of the noise
      introduced by the channel, and we can only predict the
      probability of occurrence. Since bits are transmitted at a rate
      RR, errors occur at an average
      frequency of
      
	R
	    
	      p
	      e
	    
	  
      
	  
	  R
	  
	    
	      p
	      e
	    
	  
	.  Suppose the error probability is an impressively
      small number like
      
	10-6
      
	  
	  10
	  -6
	.  Data on a computer network like Ethernet is
      transmitted at a rate 
      
	R=100Mbps
      
	  
	  R
	  
	    
	    100
	    Mbps
	  
	, which means that errors would occur roughly 100 per
      second. This error rate is very high, requiring a much smaller
      		  
	
	  
	    p
	    e
	  
	
      
	  
	    p
	    e
	  
	
      to achieve a more acceptable average occurrence rate for errors
      occurring. Because Ethernet is a wireline channel, which means
      the channel noise is small and the attenuation low, obtaining
      very small error probabilities is not difficult. We do have some
      tricks up our sleeves, however, that can essentially reduce the
      error rate to zero without resorting to
      expending a large amount of energy at the transmitter.  We need
      to understand digital
      channels and Shannon's Noisy Channel Coding Theorem.
    
   
        
"Electrical Engineering Digital Processing Systems in Braille."