In frequency-shift keying (FSK), the bit
      affects the frequency of a carrier sinusoid.
      
	
	  
		
		  s
		  0
		
	      t=A
		  
		    p
		    T
		  
		tsin2π
		    
		      f
		      0
		    
		  t
	
	    
	    
	      
		
		  s
		  0
		
	      
	      t
	    
	    
	      
	      A
	      
		
		  
		    p
		    T
		  
		
		t
	      
	      
		
		
		  
		  2
		  
		  
		    
		      f
		      0
		    
		  
		  t
		
	      
	    
	  
      
(1) 
	
	  
		
		  s
		  1
		
	      t=A
		  
		    p
		    T
		  
		tsin2π
		    
		      f
		      1
		    
		  t
	
	    
	    
	      
		
		  s
		  1
		
	      
	      t
	    
	    
	      
	      A
	      
		
		  
		    p
		    T
		  
		
		t
	      
	      
		
		
		  
		  2
		  
		  
		    
		      f
		      1
		    
		  
		  t
		
	      
	    
	  
    
     
    
      The frequencies
      
	
	  
	    f
	    0
	  
	
      
	  
	    f
	    0
	  
	, 
      
	
	  
	    f
	    1
	  
	
      
	  
	    f
	    1
	  
	
      are usually harmonically related to the bit interval.  In the
      depicted example,
      
	
	    
	      f
	      0
	    
	  =3T
      
	  
	  
	    
	      f
	      0
	    
	  
	  
	    
	    3
	    T
	  
	
      and 
      
	
	    
	      f
	      1
	    
	  =4T
      
	  
	  
	    
	      f
	      1
	    
	  
	  
	    
	    4
	    T
	  
	.  As can be seen from the transmitted signal for our
      example bit stream (Figure 2), the
      transitions at bit interval boundaries are smoother than those
      of BPSK.
    
    
    
    To determine the bandwidth required by this signal set, we again
      consider the alternating bit stream.  Think of it as two signals
      added together: The first comprised of the signal
      
	
	    
	      s
	      0
	    
	  t
      
	  
	    
	      s
	      0
	    
	  
	  t
	, the zero signal,
      
	
	    
	      s
	      0
	    
	  t
      
	  
	    
	      s
	      0
	    
	  
	  t
	, zero, etc., and the second having
      the same structure but interleaved with the first and containing
	
	    
	      s
	      1
	    
	  t
      
	  
	    
	      s
	      1
	    
	  
	  t
	 (Figure 3).
    
    
    
    
      Each component can be thought of as a fixed-frequency sinusoid
      multiplied by a square wave of period
      
	2T
      
	    2
	    T
	
      that alternates between one and zero.  This baseband square wave
      has the same Fourier spectrum as our BPSK example, but with the
      addition of the constant term
      
	
	  
	    c
	    0
	  
	
      
	  
	    c
	    0
	  
	.  This quantity's presence changes the number of
      Fourier series terms required for the 90% bandwidth: Now we need
      only include the zero and first harmonics to achieve it.  The
      bandwidth thus equals, with
      
	
	    
	      f
	      0
	    
	  <
	    
	      f
	      1
	    
	  
      
	  
	  
	    
	      f
	      0
	    
	  
	  
	    
	      f
	      1
	    
	  
	,
      
	
		
		  f
		  1
		
	      +12T−(
		
		  f
		  0
		
	      −12T)=
		
		  f
		  1
		
	      −
		
		  f
		  0
		
	      +1T
      
	  
	  
	    
	    
	      
	      
		
		  f
		  1
		
	      
	      
		
		1
		
		  
		  2
		  T
		
	      
	    
	    
	      
	      
		
		  f
		  0
		
	      
	      
		
		1
		
		  
		  2
		  T
		
	      
	    
	  
	  
	    
	    
	      
	      
		
		  f
		  1
		
	      
	      
		
		  f
		  0
		
	      
	    
	    
	      
	      1
	      T
	    
	  
	.  If the two frequencies are harmonics of the
      bit-interval duration,
    
      
	  
	    f
	    0
	  
	=
	    
	      k
	      0
	    
	  T
    
	
	  
	    f
	    0
	  
	
	
	  
	    
	      k
	      0
	    
	  
	  T
	
       and
    
      
	  
	    f
	    1
	  
	=
	    
	      k
	      1
	    
	  T
    
	
	  
	    f
	    1
	  
	
	
	  
	    
	      k
	      1
	    
	  
	  T
	
       with
    
      
	  
	    k
	    1
	  
	>
	  
	k
	    0
	  
	
    
	
	  
	    k
	    1
	  
	
	
	  
	k
	    0
	  
	
      , the bandwidth equals
    
      
	    
	      k
	      1
	    
	  +−
              
	        k
	        0
	      
	    +1T
    
        
	  
	    
	      k
	      1
	    
	  
	  
            
              
	        k
	        0
	      
	    
          
          1
         
         T
      .  If the difference between harmonic numbers is
     11, then the FSK bandwidth is
     smaller than the BPSK bandwidth.  If the
     difference is 22, the bandwidths are
     equal and larger differences produce a transmission bandwidth
     larger than that resulting from using a BPSK signal set.
    
   
        
"Electrical Engineering Digital Processing Systems in Braille."