When we consider the much more realistic situation when we have
a channel that introduces attenuation and noise, we can make use
of the just-described receiver's linear nature to directly
derive the receiver's output. The attenuation affects the output
in the same way as the transmitted signal: It scales the output
signal by the same amount. The white noise, on the other hand,
should be filtered from the received signal before
demodulation. We must thus insert a bandpass filter having
bandwidth
2W
2
W
and center frequency
f
c
f
c
: This filter has no effect on the received
signal-related component, but does remove out-of-band noise
power. As shown in the triangular-shaped signal spectrum, we apply
coherent receiver to this filtered signal, with the result that
the demodulated output contains noise that cannot be removed: It
lies in the same spectral band as the signal.
As we derive the signal-to-noise ratio in the demodulated
signal, let's also calculate the signal-to-noise ratio of the
bandpass filter's output
r
˜
t
r
˜
t
. The signal component of
r
˜
t
r
˜
t
equals
α
A
c
mtcos2π
f
c
t
α
A
c
m
t
2
f
c
t
. This signal's Fourier transform equals
α
A
c
2(Mf+
f
c
+Mf−
f
c
)
α
A
c
2
M
f
f
c
M
f
f
c
(1)
making the power spectrum,
α2
A
c
24(|Mf+
f
c
|2+|Mf−
f
c
|2)
α
2
A
c
2
4
M
f
f
c
2
M
f
f
c
2
(2)
If you calculate the magnitude-squared of the first
equation, you don't obtain the second unless you make an
assumption. What is it?
The key here is that the two spectra
Mf−
f
c
M
f
f
c
,
Mf+
f
c
M
f
f
c
do not overlap because we have assumed that the carrier frequency
f
c
f
c
is much greater than the signal's highest frequency.
Consequently, the term
Mf−
f
c
Mf+
f
c
M
f
f
c
M
f
f
c
normally obtained in computing the magnitude-squared equals
zero.
Thus, the total signal-related power in
r
˜
t
r
˜
t
is
α2
A
c
22powerm
α
2
A
c
2
2
power
m
.
The noise power equals the integral of the noise power spectrum;
because the power spectrum is constant over the transmission
band, this integral equals the noise amplitude
N
0
N
0
times the filter's bandwidth
2W
2
W
. The so-called received signal-to-noise
ratio — the signal-to-noise ratio after the
de rigeur front-end bandpass filter and
before demodulation — equals
SNR
r
=α2
A
c
2powerm4
N
0
W
SNR
r
α
2
A
c
2
power
m
4
N
0
W
(3)
The demodulated signal
m
^
t=α
A
c
mt2+
n
out
t
m
^
t
α
A
c
m
t
2
n
out
t
. Clearly, the signal power equals
α2
A
c
2powerm4
α
2
A
c
2
power
m
4
. To determine the noise power, we must understand how
the coherent demodulator affects the bandpass noise found in
r
˜
t
r
˜
t
. Because we are concerned with noise, we must deal
with the power spectrum since we don't have the Fourier
transform available to us. Letting
P
ñ
f
P
ñ
f
denote the power spectrum of
r
˜
t
r
˜
t
's noise component, the power spectrum after
multiplication by the carrier has the form
P
ñ
f+
f
c
+
P
ñ
f−
f
c
4
P
ñ
f
f
c
P
ñ
f
f
c
4
(4)
The delay and advance in frequency indicated here results in two
spectral noise bands falling in the low-frequency region of
lowpass filter's passband. Thus, the total noise power in this
filter's output equals
2·
N
0
2·W·2·14=
N
0
W2
·
2
N
0
2
W
2
1
4
N
0
W
2
.
The signal-to-noise ratio of the receiver's output thus equals
SNR
m
^
=α2
A
c
2powerm2
N
0
W=2
SNR
r
SNR
m
^
α
2
A
c
2
power
m
2
N
0
W
2
SNR
r
(5)
Let's break down the components of this signal-to-noise ratio to
better appreciate how the channel and the transmitter parameters
affect communications performance. Better performance, as
measured by the SNR, occurs as it
increases.
- More transmitter power — increasing
A
c
A
c
— increases the signal-to-noise
ratio proportionally.
- The carrier frequency
f
c
f
c
has no effect on SNR, but we have assumed that
f
c
≫W
≫
f
c
W
.
- The signal bandwidth WW enters the
signal-to-noise expression in two places: implicitly through
the signal power and explicitly in the expression's
denominator. If the signal spectrum had a
constant amplitude as we increased the bandwidth,
signal power would increase proportionally. On the other
hand, our transmitter enforced the criterion that signal amplitude was
constant. Signal amplitude essentially equals the
integral of the magnitude of the signal's spectrum.
This result isn't exact, but we do know that
m0=∫−∞∞Mfdf
m
0
f
M
f
.
Enforcing the signal amplitude specification means that as
the signal's bandwidth increases we must decrease the
spectral amplitude, with the result that the signal power
remains constant. Thus, increasing signal bandwidth does
indeed decrease the signal-to-noise ratio of the receiver's
output.
- Increasing channel attenuation — moving the
receiver farther from the transmitter — decreases the
signal-to-noise ratio as the square. Thus, signal-to-noise
ratio decreases as distance-squared between transmitter and
receiver.
- Noise added by the channel adversely affects the
signal-to-noise ratio.
In summary, amplitude modulation provides an effective means for
sending a bandlimited signal from one place to another. For
wireline channels, using baseband or amplitude modulation makes
little difference in terms of signal-to-noise ratio. For
wireless channels, amplitude modulation is the only
alternative. The one AM parameter that does not affect
signal-to-noise ratio is the carrier frequency
f
c
f
c
: We can choose any value we want so long as the
transmitter and receiver use the same value. However, suppose
someone else wants to use AM and chooses the same carrier
frequency. The two resulting transmissions will add, and
both receivers will produce the sum of the
two signals. What we clearly need to do is talk to the other
party, and agree to use separate carrier frequencies. As more
and more users wish to use radio, we need a forum for agreeing
on carrier frequencies and on signal bandwidth. On earth, this
forum is the government. In the United States, the Federal
Communications Commission (FCC) strictly controls the use of the
electromagnetic spectrum for communications. Separate frequency
bands are allocated for commercial AM, FM, cellular telephone
(the analog version of which is AM), short wave (also AM), and
satellite communications.
Suppose all users agree to use the same signal bandwidth.
How closely can the carrier frequencies be while avoiding
communications crosstalk? What is the signal bandwidth for
commercial AM? How does this bandwidth compare to the
speech bandwidth?
Separation is
2W
2
W
. Commercial AM signal bandwidth is
5kHz
5
kHz
. Speech is well contained in this bandwidth, much
better than in the telephone!
"Electrical Engineering Digital Processing Systems in Braille."