The results shown in other modules
(circuit elements,
KVL and KCL,
interconnection laws)
with regard to this
circuit, and the values of other currents and voltages in this
circuit as well, have profound implications.
Resistors connected in such a way that current from one must
flow only into another—currents in
all resistors connected this way have the same
magnitude—are said to be connected in
series. For the two series-connected resistors in
the example, the voltage across one resistor equals
the ratio of that resistor's value and the sum of resistances
times the voltage across the series combination. This
concept is so pervasive it has a name: voltage
divider.
The input-output relationship for this system,
found in this particular case by voltage divider, takes the form
of a ratio of the output voltage to the input voltage.
v
out
v
in
=
R
2
R
1
+
R
2
v
out
v
in
R
2
R
1
R
2
In this way, we express how the components used to build the
system affect the input-output relationship. Because this
analysis was made with ideal circuit elements, we might expect
this relation to break down if the input amplitude is too high
(Will the circuit survive if the input changes from 1 volt to
one million volts?) or if the source's frequency becomes too
high. In any case, this important way of expressing input-output
relationships—as a ratio of output to
input—pervades circuit and system theory.
The current
i
1
i
1
is the current flowing out of the voltage source. Because it equals
i
2
i
2
,
we have that
v
in
i
1
=
R
1
+
R
2
v
in
i
1
R
1
R
2
:
The series combination of two resistors acts, as far as the
voltage source is concerned, as a single resistor having a
value equal to the sum of the two resistances.
This result is the first of several
equivalent circuit ideas: In many cases, a
complicated circuit when viewed from its terminals (the two
places to which you might attach a source) appears to be a
single circuit element (at best) or a simple combination of
elements at worst. Thus, the equivalent circuit for a series
combination of resistors is a single resistor having a
resistance equal to the sum of its component resistances.
Thus, the circuit the voltage source "feels" (through the
current drawn from it) is a single resistor having resistance
R
1
+
R
2
R
1
R
2
.
Note that in making this equivalent circuit, the output voltage
can no longer be defined: The output resistor labeled
R
2
R
2
no longer appears. Thus, this equivalence is made strictly from
the voltage source's viewpoint.
One interesting simple circuit
(Figure 3)
has two resistors connected side-by-side, what we will term a
parallel connection, rather than in series.
Here, applying KVL reveals that all the voltages are identical:
v
1
=v
v
1
v
and
v
2
=v
v
2
v
.
This result typifies parallel connections. To write the KCL
equation, note that the top node consists of the entire upper
interconnection section. The KCL equation is
i
in
−
i
1
−
i
2
=0
i
in
i
1
i
2
0
.
Using the v-i relations, we find that
i
out
=
R
1
R
1
+
R
2
i
in
i
out
R
1
R
1
R
2
i
in
Suppose that you replaced the current source in
Figure 3
by a voltage source. How would
i
out
i
out
be related to the source voltage? Based on this result,
what purpose does this revised circuit have?
Replacing the current source by a voltage source does not
change the fact that the voltages are
identical. Consequently,
v
in
=
R
2
i
out
v
in
R
2
i
out
or
i
out
=
v
in
R
2
i
out
v
in
R
2
.
This result does not depend on the resistor
R
1
R
1
,
which means that we simply have a resistor
(
R
2
R
2
)
across a voltage source. The two-resistor circuit has no
apparent use.
This circuit highlights some important properties of parallel
circuits. You can easily show that the parallel combination of
R
1
R
1
and
R
2
R
2
has the v-i relation of a resistor having
resistance
1
R
1
+1
R
2
−1=
R
1
R
2
R
1
+
R
2
1
R
1
1
R
2
1
R
1
R
2
R
1
R
2
.
A shorthand notation for this quantity is
R
1
∥
R
2
∥
R
1
R
2
. As the reciprocal of resistance is conductance,
we can say that
for a parallel combination of resistors, the equivalent
conductance is the sum of the conductances.
Similar to voltage
divider for series resistances, we have current
divider for parallel resistances. The current through a
resistor in parallel with another is the ratio of the
conductance of the first to the sum of the conductances. Thus,
for the depicted circuit,
i
2
=
G
2
G
1
+
G
2
i
i
2
G
2
G
1
G
2
i
. Expressed in terms of resistances, current divider
takes the form of the resistance of the
other resistor divided by the sum of
resistances:
i
2
=
R
1
R
1
+
R
2
i
i
2
R
1
R
1
R
2
i
.
Suppose we want to pass the output signal into a voltage
measurement device, such as an oscilloscope or a voltmeter. In
system-theory terms, we want to pass our circuit's output to a
sink. For most applications, we can represent these measurement
devices as a resistor, with the current passing through it
driving the measurement device through some type of display.
In circuits, a sink is called a load; thus, we
describe a system-theoretic sink as a load resistance
R
L
R
L
.
Thus, we have a complete system built from a cascade of three
systems: a source, a signal processing system (simple as it is),
and a sink.
We must analyze afresh how this revised circuit, shown in
Figure 6,
works. Rather than defining eight variables and solving for the
current in the load resistor, let's take a hint from
other analysis
(series rules,
parallel rules).
Resistors
R
2
R
2
and
R
L
R
L
are in a parallel configuration: The voltages
across each resistor are the same while the currents are
not. Because the voltages are the same, we can find the current
through each from their v-i relations:
i
2
=
v
out
R
2
i
2
v
out
R
2
and
i
L
=
v
out
R
L
i
L
v
out
R
L
.
Considering the node where all three resistors join, KCL says
that the sum of the three currents must equal zero. Said another
way, the current entering the node through
R
1
R
1
must equal the sum of the other two currents leaving the
node. Therefore,
i
1
=
i
2
+
i
L
i
1
i
2
i
L
,
which means that
i
1
=
v
out
(1
R
2
+1
R
L
)
i
1
v
out
1
R
2
1
R
L
.
Let
R
eq
R
eq
denote the equivalent resistance of the parallel combination of
R
2
R
2
and
R
L
R
L
. Using
R
1
R
1
's
v-i relation, the voltage across it is
v
1
=
R
1
v
out
R
eq
v
1
R
1
v
out
R
eq
.
The KVL equation written around the leftmost loop has
v
in
=
v
1
+
v
out
v
in
v
1
v
out
;
substituting for
v
1
v
1
,
we find
v
in
=
v
out
(
R
1
R
eq
+1)
v
in
v
out
R
1
R
eq
1
or
v
out
v
in
=
R
eq
R
1
+
R
eq
v
out
v
in
R
eq
R
1
R
eq
Thus, we have the input-output relationship for our entire
system having the form of voltage divider, but it does
not equal the input-output relation of the
circuit without the voltage measurement device. We can not
measure voltages reliably unless the measurement device has
little effect on what we are trying to measure. We should look
more carefully to determine if any values for the load
resistance would lessen its impact on the circuit. Comparing the
input-output relations before and after, what we need is
R
eq
≃
R
2
R
eq
R
2
.
As
R
eq
=1
R
2
+1
R
L
−1
R
eq
1
R
2
1
R
L
1
,
the approximation would apply if
1
R
2
≫1
R
L
≫
1
R
2
1
R
L
or
R
2
≪
R
L
≪
R
2
R
L
.
This is the condition we seek:
Voltage measurement devices must have large resistances
compared with that of the resistor across which the voltage is
to be measured.
Let's be more precise: How much larger would a load
resistance need to be to affect the input-output relation by
less than 10%? by less than 1%?
R
eq
=
R
2
1+
R
2
R
L
R
eq
R
2
1
R
2
R
L
.
Thus, a 10% change means that the ratio
R
2
R
L
R
2
R
L
must be less than 0.1. A 1% change means that
R
2
R
L
<0.01
R
2
R
L
0.01
.
We want to find the total resistance of the example
circuit. To apply the series and parallel combination rules,
it is best to first determine the circuit's structure: What is
in series with what and what is in parallel with what at both
small- and large-scale views. We have
R
2
R
2
in parallel with
R
3
R
3
;
this combination is in series with
R
4
R
4
.
This series combination is in parallel with
R
1
R
1
.
Note that in determining this structure, we started
away from the terminals, and worked
toward them. In most cases, this approach works well; try it
first. The total resistance expression mimics the structure:
R
T
=
R
1
∥(
R
2
∥
R
3
+
R
4
)
R
T
R
1
∥
R
2
∥
R
3
R
4
R
T
=
R
1
R
2
R
3
+
R
1
R
2
R
4
+
R
1
R
3
R
4
R
1
R
2
+
R
1
R
3
+
R
2
R
3
+
R
2
R
4
+
R
3
R
4
R
T
R
1
R
2
R
3
R
1
R
2
R
4
R
1
R
3
R
4
R
1
R
2
R
1
R
3
R
2
R
3
R
2
R
4
R
3
R
4
Such complicated expressions typify circuit "simplifications."
A simple check for accuracy is the units: Each component of
the numerator should have the same units (here
Ω3
Ω
3
)
as well as in the denominator
(
Ω2
Ω
2
).
The entire expression is to have units of resistance; thus,
the ratio of the numerator's and denominator's units should be
ohms. Checking units does not guarantee accuracy, but can
catch many errors.
Another valuable lesson emerges from this example concerning the
difference between cascading systems and cascading circuits. In
system theory, systems can be cascaded without changing the
input-output relation of intermediate systems. In cascading
circuits, this ideal is rarely true unless
the circuits are so
designed. Design is in the hands of the
engineer; he or she must recognize what have come to be known as
loading effects. In our simple circuit, you might think that
making the resistance
R
L
R
L
large enough would do the trick. Because the resistors
R
1
R
1
and
R
2
R
2
can have virtually any value, you can never make the resistance
of your voltage measurement device big enough. Said another way,
a circuit cannot be designed in isolation that will
work in cascade with all other circuits. Electrical
engineers deal with this situation through the notion of
specifications: Under what conditions will
the circuit perform as designed? Thus, you will find that
oscilloscopes and voltmeters have their internal resistances
clearly stated, enabling you to determine whether the voltage
you measure closely equals what was present before they were
attached to your circuit. Furthermore, since our resistor
circuit functions as an attenuator, with the attenuation (a
fancy word for gains less than one) depending only on the ratio
of the two resistor values
R
2
R
1
+
R
2
=1+
R
1
R
2
−1
R
2
R
1
R
2
1
R
1
R
2
1
,
we can select any values for the two
resistances we want to achieve the desired attenuation. The
designer of this circuit must thus specify not only what the
attenuation is, but also the resistance values employed so that
integrators—people who put systems together from
component systems—can combine systems together and have a
chance of the combination working.
Figure 8
summarizes the series and parallel combination results. These
results are easy to remember and very useful. Keep in mind that
for series combinations, voltage and resistance are the key
quantities, while for parallel combinations current and
conductance are more important. In series combinations, the
currents through each element are the same; in parallel ones,
the voltages are the same.
Contrast a series combination of resistors with a parallel
one. Which variable (voltage or current) is the same for
each and which differs? What are the equivalent resistances?
When resistors are placed in series, is the equivalent
resistance bigger, in between, or smaller than the component
resistances? What is this relationship for a parallel
combination?
In a series combination of resistors, the current is the
same in each; in a parallel combination, the voltage is the
same. For a series combination, the equivalent resistance is
the sum of the resistances, which will be larger than any
component resistor's value; for a parallel combination, the
equivalent conductance is the sum of the component
conductances, which is larger than any component
conductance. The equivalent resistance is therefore smaller
than any component resistance.
"Electrical Engineering Digital Processing Systems in Braille."