1 00:00:00,25 --> 00:00:06,845 [MUSIC] We could figure out our anti derivative for log x, by just guessing 2 00:00:06,845 --> 00:00:13,977 and then checking our answer. But we can also get that anti derivative 3 00:00:13,977 --> 00:00:18,923 by using integration by parts. So I want to know an anti derivative of , 4 00:00:18,923 --> 00:00:22,618 log x dx. And just to remind you, this is natural 5 00:00:22,618 --> 00:00:25,487 log. At first, it looks like there's nothing 6 00:00:25,487 --> 00:00:29,120 helpful here. What would my u and my dv be? 7 00:00:29,120 --> 00:00:34,632 The trick is to sit u log x that's the part of the anagram I'm going to 8 00:00:34,632 --> 00:00:41,711 differentiate as dv. To be dx and it gets quite surprising, 9 00:00:41,711 --> 00:00:47,320 and that helps. Let's see, so if u is log x then du is 1 10 00:00:47,320 --> 00:00:53,826 over x dx. And if dv is dx then an anti-derivative, 11 00:00:53,826 --> 00:00:57,580 just be x. Now, what does parts tell us? 12 00:00:57,580 --> 00:01:06,523 So by parts the integral of u dv, so log x dx, that's what I'm interested in. 13 00:01:06,523 --> 00:01:14,125 Is u v so x log x minus the integral of vdu, which is x times du. 14 00:01:14,125 --> 00:01:19,900 And I've got x log x minus x times 1 over x, that's just 1. 15 00:01:19,900 --> 00:01:24,825 So I'm just anti-differentiating dx. Then I've got x log x, what's an 16 00:01:24,825 --> 00:01:30,420 anti-derviative of 1, just x, and I'll add a constant. 17 00:01:30,420 --> 00:01:34,934 So I'm claiming that the antiderivative of log x is x log x minus x plus some 18 00:01:34,934 --> 00:01:39,824 constant. I think it's really surprising that, at 19 00:01:39,824 --> 00:01:44,380 least in this case, dv equals dx is a great choice. 20 00:01:44,380 --> 00:01:47,308 Well here's a similar integration problem that you can try the same kind of 21 00:01:47,308 --> 00:01:50,500 technique on. For example, here's a challenge. 22 00:01:50,500 --> 00:02:02,373 Can you find an anti derivative of log of x squared?