1 00:00:00,025 --> 00:00:06,570 [music]. Let's suppose that I have a formula for my 2 00:00:06,570 --> 00:00:11,260 velocity. For instance I made my velocity at time t 3 00:00:11,260 --> 00:00:16,615 is something like 3 minus 10 times t. With that equation in hand, can I then 4 00:00:16,615 --> 00:00:18,929 determine my position? Right? 5 00:00:18,929 --> 00:00:22,249 Velocity and position are related in some way. 6 00:00:22,250 --> 00:00:25,773 The derivative of my position is, well let's, let's write that fact down. 7 00:00:25,774 --> 00:00:36,573 P of t is my position at time t. V of t is my velocity at time t. 8 00:00:36,573 --> 00:00:40,919 And the crucial thing here is if the derivative of my position, right? 9 00:00:40,919 --> 00:00:43,770 The rate of change of my position is velocity. 10 00:00:43,770 --> 00:00:48,791 So, the derivative of p is v. So, I've written that as a derivative 11 00:00:48,791 --> 00:00:52,914 statement but I could also write it as an antiderivative statement. 12 00:00:52,914 --> 00:00:58,422 So, I can write that p of t is an antiderivative of v of t, right? 13 00:00:58,422 --> 00:01:05,127 Because p differentiates to v, the antiderivative of v is p. 14 00:01:05,128 --> 00:01:09,787 Now, I want to use the fact that my velocity at time t is 3 minus 10t. 15 00:01:09,787 --> 00:01:17,884 That means in our specific case that my position, being the antiderivative of the 16 00:01:17,884 --> 00:01:22,141 velocity and velocity is 3 minus 10t, right? 17 00:01:22,141 --> 00:01:25,621 So, my position is the antiderivative of my velocity. 18 00:01:25,621 --> 00:01:28,896 And we can solve that antidifferentiation problem. 19 00:01:28,896 --> 00:01:30,690 Well, here we go. Alright? 20 00:01:30,690 --> 00:01:35,410 This is the antiderivative of a difference, which is the difference of 21 00:01:35,410 --> 00:01:39,224 antiderivatives. Now, I'd like to antidifferentiate 3, 22 00:01:39,224 --> 00:01:43,626 would be antiderivative of a constant such that constant times t. 23 00:01:43,626 --> 00:01:46,946 And what's an antiderivative of 10 times t? 24 00:01:46,946 --> 00:01:50,598 Well, that's 10 times an antiderivative for t. 25 00:01:50,598 --> 00:01:55,080 So, I got 3t minus 10 times. What's an antiderivative for t? 26 00:01:55,080 --> 00:01:59,399 By the power rule, an antiderivative for t is t squared over 2. 27 00:01:59,399 --> 00:02:04,770 And if I differentiate this, I get back t. I'm going to include a plus C here. 28 00:02:04,770 --> 00:02:13,807 So I can rewrite this as 3t minus 5t squared plus some constant C. 29 00:02:13,808 --> 00:02:19,397 And now, that plus C has a perfectly reasonable physical interpretation. 30 00:02:19,398 --> 00:02:24,624 If I know my velocity, I know my position as long as I know my initial position, as 31 00:02:24,624 --> 00:02:29,717 long as I know where I started, right? And that's what that plus C is encoding. 32 00:02:29,718 --> 00:02:35,760 If I knew for instance that my position at times 0 were say 4 units, then I could 33 00:02:35,760 --> 00:02:42,944 figure out what C would have to be right. That would tell me my position at some 34 00:02:42,944 --> 00:02:49,350 time t, be 3t minus 5t squared plus 4. This is an example where knowing my 35 00:02:49,350 --> 00:02:54,710 initial position, my position at time 0, and knowing my velocity for all time, is 36 00:02:54,710 --> 00:02:59,278 enough to figure out my position. In very fancy terms, this is an example of 37 00:02:59,278 --> 00:03:06,719 solving a differential equation. I started with the derivative information, 38 00:03:06,719 --> 00:03:16,933 and by antidifferentiating, I recovered the original function, up to a constant.