[MUSIC] What's the derivative of a 
product of two functions? The derivative 
of a product is given by this, the 
Product Rule. 
The derivative of f times g is the 
derivative of f times g plus f times the 
derivative of g. 
It's a bunch of things to be warned about 
here. 
This is the product of two functions, but 
the derivative involves the sum of two 
different products. 
It's the derivative of the first times 
the second plus the first times the 
derivative of the second. 
Let's see an example of this rule in 
action. 
For example, let's work out the 
derivative of this product, the product 
of 1+2x and 1+x^2. 
Alright, well here we go. This is a 
derivative of product, so by the Product 
Rule, I'm going to differentiate the 
first thing, multiply by the second, and 
add that to the first thing times the 
derivative of the second. 
So, it's the derivative of the first term 
in the product times the second term in 
the product, derivative of the first 
function times the second, plus the first 
function, 1+2x, times the derivative of 
the second. 
So, that's an instance of the Product 
Rule. 
Now, this is the derivative of a sum, 
which is the sum of the derivatives. 
So, it's the derivative of 1 plus the 
derivative of 2x times 1+x^2 plus 1+2x 
times the derivative of a sum, which is 
the sum of the derivatives. 
Now, the derivative of 1, that's a 
derivative of a constant function that's 
just 0, 
this is the derivative of a constant 
multiple so I can pull that constant 
multiple out of the derivative, 
times 1+x^2+1+2x times, the derivative of 
1 is 0, 
it's the derivative of a constant, plus 
the derivative of x^2 is 2x. 
Alright. 
Now, I've got 0+2 times the derivative of 
x. 
The derivative of x is just 1. 
So, that's just 
2*1*(1+x^2)+(1+2x)*(0+2x). 
So, there it is. 
I could maybe write this a little bit 
more neatly. 
2*(1+x^2)+(1+2x)*2x. 
This is the derivative of our original 
function (1+2x)*(1+x^2). 
We din't really need the Product Rule to 
compute that derivative. 
So, instead of using the Product Rule on 
this, I'm going to first multiply this 
out and then do the differentiation. 
Here, watch. 
So, this is the derivative but I'm going 
to multiply all this out, alright? So, 
1+2x^3, which is what I get when I 
multiply 2x by x^2, plus x^2, which is 
1*x^2+2x*1. 
So now, I could differentiate this 
without using the Product Rule, right? 
This is the derivatives of big sum, 
so it's the sum of the derivatives. 
The derivative of one, the derivative of 
2x^3, the derivative of x^2, and the 
derivative of 2x. 
Now, the derivative of 1, that's the 
derivative of a constant, 
that's just 0. 
The derivative of this constant multiple 
of x^3, I can pull out the constant 
multiple. 
The derivative of x^2 is 2x and the 
derivative of 2-x, so I can pull out the 
constant multiple. 
Now, what's 2 times the derivative of 
x^3? That's 2 times, the derivative of 
x^3 is 3x^2+2x+2 times the derivative of 
x, which is 2*1. 
And then, I could write this maybe a 
little bit more nicely. 
This is 6x^2+2x+2. 
So, this is the derivative of our 
original function. 
Woah. What just happened? I'm trying to 
differentiate 1+2x*1+x^2. 
When I just used the Product Rule, I got 
this, 2*(1+x^2)+(1+2x)*(2x). 
When I expanded and then differentiated, 
I got this, 
6x^2+2x+2. 
So, are these two answers the same? Yeah. 
These two answers are the same. 
let's see how. 
I can expand out this first answer. 
This is 2*1+2x^2+1*2x plus 2x*2x is 4x^2. 
Now look, 
2, 2x^2+4x^2 gives me 6x^2. 
And 1*2x gives me this 2x here. 
These are, in fact, the same. 
Should we really be surprised by this? I 
mean, I did do these things in a 
different order. 
So, in this first case, I differentiated 
using the Product Rule and then I 
expanded what I got. 
In the second case, first, I expanded and 
after doing expansion, then I 
differentiated. 
More succintly in the first case, I 
differentiated than expanded. In the 
second case, I expanded then I 
differentiated. 
Look, you'd think the order would matter. 
Usually, the order does matter. 
If you take a shower and then get 
dressed, that's a totally different 
experience from getting dressed and then 
stepping into the shower. 
The order usually does matter and you'd 
think that differentiating and then 
expanding would do something really 
different than expanding and then 
differentiating. 
But you've got real choices when you do 
these derivative calculations, and yet 
somehow, Mathematics is conspiring so 
that we can all agree on the derivative, 
no matter what choices we might make on 
our way there. 
And I think we can also all agree that 
that's pretty cool. 
[MUSIC]