1 00:00:00,000 --> 00:00:00,094 So now, just making some room to, to write a little more here. Okay. So, so now, 2 00:00:00,094 --> 00:00:01,018 what, what this, what this tells us is that if you work it out, it's as though, 3 00:00:01,018 --> 00:00:01,018 you know as the slinky is precessing, as it's rotating. It's as though it's 4 00:00:01,018 --> 00:00:01,018 velocity is, is proportional to K. Okay, so, why is that? Well, you see, we, we 5 00:00:01,018 --> 00:00:01,062 already said that the period of this function, the period of this, this the 6 00:00:01,062 --> 00:00:01,069 wave function is two pi / K. And if you, if you, if you look at this, you know, 7 00:00:01,069 --> 00:00:01,077 this time dependence e^i K^2 t, the time it takes to, for this, you know, as this 8 00:00:01,077 --> 00:00:01,085 wave function is precessing to, to precess to one full circle, is actually two pi / 9 00:00:01,085 --> 00:00:01,092 K^2. And so, so the fond movement of the slinky, in, in one, one such, one such 10 00:00:01,092 --> 00:00:02,000 full rotation of the phase, is two pi / K but, but this happens in time t2 pi / K^2. 11 00:00:02,000 --> 00:00:02,008 So, the apparent velocity is this over this, so it is two pi / K / two pi / K^2, 12 00:00:02,008 --> 00:00:02,015 which is K. Okay, so, so now, what, what, what we've understood is if we, if our 13 00:00:02,015 --> 00:00:02,022 wave function looked like this, if it looks like e^ikx, then it would have a 14 00:00:02,022 --> 00:00:02,029 definite velocity of K. Okay, but we're not given, you know, but, but, we are 15 00:00:02,029 --> 00:00:02,036 given just some psi (x, t). It's not, it's not e^ikx, you know, this is those wave 16 00:00:02,036 --> 00:00:02,044 function with had the definite velocity of K. So now, we can ask what's the, you 17 00:00:02,044 --> 00:00:02,052 know, if we were to write out psi (x, t) in the, in the velocity basis, right? So, 18 00:00:02,052 --> 00:00:02,060 we could write it out in the velocity, instead of in the position basis, we could 19 00:00:02,060 --> 00:00:02,068 write it out in the velocity basis and we might have some superposition which, you 20 00:00:02,068 --> 00:00:02,076 know, which, which, which, which look like that, which would say, with what amplitude 21 00:00:02,076 --> 00:00:02,084 is the velocity of this, of this particle at time t equal to, equal to v and the 22 00:00:02,084 --> 00:00:02,091 answer would be, it's, it's this much, alright. So, this is, this is amplitude. 23 00:00:02,091 --> 00:00:02,099 Okay, so, let me, let me call it phi (v, t). So, this is the amplitude which it has 24 00:00:02,099 --> 00:00:03,006 this. And so, how do you compute phi (v, t)? Well, it's exactly the component of 25 00:00:03,006 --> 00:00:03,014 psi in the direction of this function. So, how do you compute the component of psi in 26 00:00:03,014 --> 00:00:03,021 this direction? Yo u take the inner product. The inner product of this 27 00:00:03,021 --> 00:00:03,028 function with psi (x, t) which is what? It's the integral of e^-ikx, it's the 28 00:00:03,028 --> 00:00:03,036 complex conjugate of this. Psi (x, t) dx of minus infinity to infinity. Alright, 29 00:00:03,036 --> 00:00:03,044 what's the inner product is just, you, you just, you just take the product of the 30 00:00:03,044 --> 00:00:03,052 corresponding components. Well, with, with the complex conjugate of the first one 31 00:00:03,052 --> 00:00:03,060 times the component of the second one, and then you add it over all, you know, over, 32 00:00:03,060 --> 00:00:03,068 over all the dimensions. But here, we are, we are working on continuous dimensional 33 00:00:03,068 --> 00:00:03,075 space where x is what indexes these dimensions. So, we just take complex 34 00:00:03,075 --> 00:00:03,082 conjugate of the first time. So, second and instead of summing over all the 35 00:00:03,082 --> 00:00:03,090 dimensions, now since x is continuous, we integrate this from minus infinity to 36 00:00:03,090 --> 00:00:03,098 infinity this time dx. And that's, that's the component in this direction, but now, 37 00:00:03,098 --> 00:00:04,006 some of you might recognize this function. What is this? Well, phi just the Fourier 38 00:00:04,006 --> 00:00:04,013 transform of psi, okay? So, while I'm calling it velocity here just for, you 39 00:00:04,013 --> 00:00:04,021 know, just, just for intuitive purposes. You know in quantum mechanics, we are 40 00:00:04,021 --> 00:00:04,029 really measuring momentum which is proportional to velocity. And so velocity, 41 00:00:04,029 --> 00:00:06,080 momentum is the Fourier of transform of the, of position. So, position and 42 00:00:06,080 --> 00:00:07,051 momentum are related to each other by Fourier transforms. This is a very 43 00:00:07,051 --> 00:00:07,051 interesting thing because what it says is, you start with some superposition, psi. 44 00:00:07,051 --> 00:00:07,051 So, this is psi (x). This is a, this is a, a position of a particle at, at, at 45 00:00:07,051 --> 00:00:07,051 whatever time, alight. It's, it's sum function. Alright. This is psi (x). Now, 46 00:00:07,051 --> 00:00:07,083 we write phi (p), p for momentum. Okay, so, this is, okay, let's, let's write it 47 00:00:07,083 --> 00:00:00,000 in blue. It's phi (p), okay? This is meant to be some other superposition, and what, 48 00:00:00,000 --> 00:00:00,000 what, what I'm cleaning is that the way you're getting from one to the other and 49 00:00:00,000 --> 00:00:00,000 back is by doing a Fourier transform. Okay, so, what do you know about a Fourier 50 00:00:00,000 --> 00:00:00,000 transform? The one thing you should know is that the more you concentrate a 51 00:00:00,000 --> 00:00:00,000 function in the primary domain, the more it spreads out in the Fourier domain. The 52 00:00:00,000 --> 00:00:00,000 more you try to concentrate it in the Fourier domain, the more it spreads out in 53 00:00:00,000 --> 00:00:00,000 the primary domain. So, what are you to do? Well, it turns out that the best you 54 00:00:00,000 --> 00:00:00,000 can do is sort of make, make this, this function on this side, be a Gaussian with 55 00:00:00,000 --> 00:00:00,000 some standard deviation sigma. And then, you have some corresponding standard 56 00:00:00,000 --> 00:00:00,000 deviation sigma hat on this, on this side and it turns out that the, that the 57 00:00:00,000 --> 00:00:00,000 smaller sigma is the bigger sigma hat is and vice versa. And so, you can try to 58 00:00:00,000 --> 00:00:00,000 find the happy median between the two. And this is what gives us this uncertainty 59 00:00:00,000 --> 00:00:00,000 principle which says that delta x delta p is at least h bar / two. So, delta x is 60 00:00:00,000 --> 00:00:00,000 really sigma and delta p is sigma hat and what if, you know, the, the fact about 61 00:00:00,000 --> 00:00:00,000 Fourier transforms is, is that the way you min, minimize this product is by using 62 00:00:00,000 --> 00:00:00,000 Gaussian in the first place and in, in the second place, if you use Gaussian, then, 63 00:00:00,000 --> 00:00:00,000 then the width of this Gaussian times the width of this Gaussian in the Fourier, 64 00:00:00,000 --> 00:00:00,000 Fourier transform. The product of these two bits is bounded below by some 65 00:00:00,000 --> 00:00:00,000 constant, okay? So, let me reiterate. There is not much of this lecture that you 66 00:00:00,000 --> 00:00:00,000 really need to know. But, this is, you know, this should help you get a picture 67 00:00:00,000 --> 00:00:00,000 of what's going on with continuous quantum states, with the Schrodinger equation for 68 00:00:00,000 --> 00:00:00,000 the particle on the line with, where this uncertainty principle comes from, okay? In 69 00:00:00,000 --> 00:00:00,000 the next lecture, we'll look at all of this in a more precise way.