Okay, so in this video we are going to trying to understand intuitively how the form of Schrodinger's equation for a free particle on a line. Okay, so, so remember what we have with the free particle on a line, so we have. The particle is free to be any where on the real line and, and it's described, it state is described by wave function. Which might look like this. It's um, it's psi of x at time t. So, this is maybe, this is maybe what it looks like at time t=0, at general time t, and we want to understand how this state evolves as t increases. Okay so, what we are going to do is we're gonna assume, you know, there's this one general principle that we're gonna assume that the equation of motion is described by it's, it's a local differential equation, meaning it's this very important principle in physics, which is that of locality, that every point in space, sort of, minds its own business. Well. Well, it, it minds it's own business, but it, it sorts of look around at an infinitesimal neighborhood around it. So it, it, it, um, well. It, it's mind, it minds its own business, but also the business of sort of a small neighborhood around itself. Okay. So, so, so now, what, what, what, what do we want to say? Well, we want to say that, that the change in the state. So if you want to write D Psi XT by DT. Right, the, the way this is described is by, by the following kind of differential equation, the, the, the weight of change in the state at the point X. So if this was the point X, this is the time T, that's what the super position looks like and now, what, what this point X does is it looks in its neighbourhood and it looks at a point, sort of, uh, uh, at x plus delta-x, and at x minus delta-x. So it looks in its tiny neighborhood, and so, and it looks at its own amplitude, so this is what psi of x is, and it compares it to psi of x plus delta x, and psi of x minus delta x. And it does this in a particularly simple way, so what it does is, it looks at the average of psi of x plus delta x, and psi of x minus delta x. So, so what's this average of these two points? Well, the average of these two points is, is that. Right, so, so what it's doing is it's comparing this point, which is psi of x minus delta x, oops. Plus psi of X, plus delta X divided by two and it's comparing it to, its own value which is psi of X. And basically what this, what this equation says is that if you look at this difference, the difference between these two quantities. So, this value. So let's call this Y. What Schrodinger's equation says is that the rate of change is proportional to Y. So the rate of change of psi at this point X is proportional to the difference between psi at this point X minus the average of the neighbors. And the neighbors infinite to the left and to the right. Okay, so, so now, can you, you know, as delta X turns to zero. Can you describe what this, what y is in terms of psi of x? So, so we can ask, can you describe Y in terms of psi of X? Some of you might be guessing maybe Y is, Y is just a, you know, Y is something like the derivative of the psi of X, with respect to X. Well, that's a pretty good guess, but let's, let's look at whether that's true. So, so suppose that, um, that psi of x happen to look like the straight line in this region. So, so this is psi of x. There's, there's x. Okay and there's X + delta X, X - delta X. So, what's the average of psi of X - delta of X and psi of X + delta of X. Well the average of these two points is exactly that. And so Y is exactly zero because psi of X is exactly, exactly the average of psi of X minus delta X and psi of X plus delta X. So there's something else going on here and so actually if you think about it a little bit more it turns out that Y is proportional to the second derivative of psi of X with respect to X. Okay, the, the reason, you might, you know, the way you might see this is that this difference psi of X minus delta X plus psi of X, plus delta X, minus psi of X, so this divide by two minus I X. This is the same as psi of x + delta x - psi x. I'm just putting this and this together, minus another psi X. And then I can subtract off psi of X minus delta X. Okay? So this first piece is proportional to the derivative of x of psi x at x. And this, at, at, um, and this is proportional to the derivative of psi x as, at x-delta x. So when you subtract these two, it's proportional to the second derivative. And so, what's equation says is that the rate of change of psi with respect to T. It's proportional to. So, since I don't care about constants in this particular lecture, I'm just being very imprecise, I'll just say it's equal to the second derivative of psi with respect to, X. Well not quite. So, you see if, if this is all that was happening, then, this would not be very good because what you know, what Schrodinger's equation would say is that every point then tries to look like the average of its neighbors, and no matter where you start from, your wave function would, would eventually become completely flat. So to keep it from going flat, but still to keep the change proportional to this difference, what you do is move in the orthogonal direction in the complex plane. Okay so, so let's see what, what this means. So, so remember, our, our equation now is I D psi of x, t by dt is d2 psi x, t by dx squared. Okay why, why I times this? So, let's say we are working on the complex plane, this is real, this is imaginary. And let's say we have a, we have complex number, which is like a vector in this complex plane. Okay, so. So now um, if you take this, this complex number and you instead, you know if, you, you, you could move it in some direction. So, for example, you could, you could change it. But if you change it. In a direction which is I times itself. Then you're, then you're changing it in like this. And what you're doing is you're, you're basically rotating the complex number around, and it leaves its magnitude unchanged. And so, this is the sort of thing that Schrodinger's equation is doing. It's saying, Well, the rate of change is proportional to the secondary derivative, but we wan t to move it in the orthog, you know, orthogonal direction in the complex plane. So that we actually keep the normalization of the wave function, so that it actually ends up still being a unit wave function. Okay, so, so, you know lets, lets state back and see what this is told us about Schrodinger's equation. So, what it's telling us is, if you have a free particle on a line. And there's some superposition that describes it. So, you know, it's, it's some superposition that, that, that describes it. Now, what's, what's happening to this, this superposition? Well, basically, every point looks around. It looks at its, you know, it looks, uh, every point X. Looks at its small neighborhood to the right, to the left and it compares itself to its, to its neighbors on, the average of its neighbors on the left to the right. And it changes it's amplitude at a rate which is proportional to this, this, the difference between itself and the average of its neighbors. Another way of saying it is, it changes its amplitude. At a rate that depends upon the second derivative of the wave function with respect to X. Okay, so what it means is, so now, now think of, think of at every point, you know the, the amplitude is not real it, its actually a complex number. So what you really have here. At every point is a complex plane and your amplitude is, is some complex number in this, in this complex plane. So that's real, that's imaginary. And lets say the, the amplitude happened to be imaginary right now. But now, what happens is. The amplitude starts precessing. Right it, you know, it acquires a phase. It, it starts rotating in this, in this complex plane, but at what rate does it rotate? Well it rotates at a rate which is proportional to the second derivative at this point. So, at the points where, where the wave function changes very rapidly uh, the, the second derivative is, is large. Well the, it's going to rotate quickly. But where, where the second derivative is zero, it's just not going to rotate very much at all. And that's what Schrodinger's equation tells us, about how, the way function changes in time. Okay, so now, as I said, um you know, in this form of Schrodinger's equation, I've, I've been very sloppy. I've, I've just ignored, um, uh, constant signs, etcetera. If, if you want to see what Schrodinger's equation for a free particle really looks like, well, it looks like this it, it has a form I H bar, where H bar is the reduced planck-, plancks constant D psi by DT is minus H bar squared over 2M, and it's mass of the particle, D2 psi by D x squared. Okay so we're, we're going to look at this precise form of Schrodinger's equation in the next lecture. But for now I just wanted to give you some intuitive feel about what it might be telling us about the evolution of the system.